A block is projected along a rough horizontal road with speed of 10 m/s. if the coefficient of kinetic friction is 0.10, how far will it travel before coming to rest?
coefficient of kinetic friction μ= 0.10
Initial velocity of the body u = 10m/s
Let the mass of the body= m
Weight of the body= mg N
Normal force on the body N= mg
Frictional force is given as f= μN = 0.10 mg
Deacceleration due to kinetic friction a = 
= 
= 0.10g= 0.98 m/s2
Final velocity due to deacceleration v= 0 m/s
Using equation of motion
V2 =u2 +2as
So, the distance travelled by body before coming to rest is 51 meters.
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