Two long wires carrying current I 1 and I 2 are arranged as shown in Fig. 4.1. The one carrying current I 1 is along is the x-axis. The other carrying current I2 is along a line parallel to the y-axis given by x = 0 and z = d. Find the force exerted at O 2 because of the wire along the x-axis.

Question

Philoid · Accepted Answer

According, to the above given diagram wire with current I₁ is in +ve x-axis and wire with current I �₂ is in +ve y-axis. Now, according to Biot-savart law and right-hand thumb rule magnetic field due I₁ current at O₂ is given by where,

μ_o is magnetic permeability in vacuum,

is magnetic field vector,

I₁ is current flowing in 1^st wire,

and is the displacement vector for point we want to calculate the magnetic field.

And will be in -ve y-axis direction, which means and for wire carrying I₂ current will be parallel to each other. And force on current carrying straight wire due to uniform magnetic field is given by

F= I₂ × where,

B is magnetic field strength;

I₂ is current in the wire;

is length vector of wire in direction of current.

So, since angle between and is 0^o so, F is also 0.

Hence, force on wire carrying current I₂ due to magnetic field of wire carrying current I₁ is zero (0).

Two long wires carrying current I1 and I2 are arranged as shown in Fig. 4.1. The one carrying current I1 is along is the x-axis. The other carrying current I2 is along a line parallel to the y-axis given by x = 0 and z = d. Find the force exerted at O2 because of the wire along the x-axis.

Two long wires carrying current I₁ and I₂ are arranged as shown in Fig. 4.1. The one carrying current I₁ is along is the x-axis. The other carrying current I2 is along a line parallel to the y-axis given by x = 0 and z = d. Find the force exerted at O₂ because of the wire along the x-axis.