An inductor of reactance 1Ω and a resistor of 2 Ω are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is

Given,
Inductive reactance,
Capacitive reactance,
Resistance,
Rms voltage,


The average power dissipated by resistor (power is NEVER dissipated by inductor or capacitor) of resistance R in any ac circuit with rms current Irms is given by:



Now,



where Vrms is the rms voltage and Z is impedance given by:


Reactance,


Now,



We can now calculate the power dissipated:





Hence, the correct answer is (c). No other option matches the calculated value.

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