A square of side L meters lies in the x-y plane in a region, where the magnetic field is given by Tesla, where B 0 is constant. The magnitude of flux passing through the square is

Question

Philoid · Accepted Answer

As we know that area vector is perpendicular to the plane of any polygon. So here square is in x-y plane then its area vector in z direction i.e.

Also we know, magnetic flux is the dot product of magnetic field vector and area vector

Given that putting the value of B and A in above equation i.e.

As we know that same unit vector is 1 and rest of all are zero because î,ĵ, k are all perpendicular to each other i.e.

So option c is matching with our solution rest are not.

Therefore, (c) is the correct answer.

A square of side L meters lies in the x-y plane in a region, where the magnetic field is given by Tesla, where B0 is constant. The magnitude of flux passing through the square is

A square of side L meters lies in the x-y plane in a region, where the magnetic field is given by Tesla, where B₀ is constant. The magnitude of flux passing through the square is