The circuit in Fig 3.6 shows two cells connected in opposition to each other. Cell E₁ is of emf 6V and internal resistance 2 Ω; the cell E₂ is of emf 4V and internal resistance 8Ω. Find the potential difference between the points A and B.

Question

Philoid · Accepted Answer

Given:

E₁=6V , r₁=2Ω

E₂=4V , r₂=8Ω

Total emf in this circuit is E₁–E₂, as E₁>E₂

Current flowing through the circuit = I =

Hence, potential difference between point A and B

The circuit in Fig 3.6 shows two cells connected in opposition to each other. Cell E1 is of emf 6V and internal resistance 2 Ω; the cell E2 is of emf 4V and internal resistance 8Ω. Find the potential difference between the points A and B.

The circuit in Fig 3.6 shows two cells connected in opposition to each other. Cell E₁ is of emf 6V and internal resistance 2 Ω; the cell E₂ is of emf 4V and internal resistance 8Ω. Find the potential difference between the points A and B.