The charge on a parallel plate capacitor varies as . The plates are very large and close together (area = A, separation = d). Neglecting the edge effects, find the displacement current through the capacitor?

Question

Philoid · Accepted Answer

Given

The charge stored in the capacitor q = q₀cos2πνt.

The displacement current between the plates of a capacitor is given as,

Where, is the electric flux between the plates, which can be determined by using the Gauss’s law

Gauss’s law states that the net electric flux enclosed through a closed surface is equal to the charge enclosed within the surface divided by the permittivity i.e

Therefore, the flux,

Hence, the displacement current is then,

The charge on a parallel plate capacitor varies as .The plates are very large and close together (area = A, separation = d). Neglecting the edge effects, find the displacement current through the capacitor?

The charge on a parallel plate capacitor varies as .
The plates are very large and close together (area = A, separation = d). Neglecting the edge effects, find the displacement current through the capacitor?