The magnetic field of a beam emerging from a filter facing a floodlight is given by B 0 = 12 × 10 –8 sin (1.20 × 10 7 z – 3.60 × 10 15 t) T. What is the average intensity of the beam?

Question

Philoid · Accepted Answer

Given

The equation of magnetic field of the beam

B₀ = 12 × 10^–8 sin (1.20 × 10⁷ z – 3.60 × 10¹⁵ t) T

Comparing the given equation with the general equation of magnetic field i.e.

We have,

We know that the average intensity of an electromagnetic wave is given as

The magnetic field of a beam emerging from a filter facing a floodlight is given byB0 = 12 × 10–8 sin (1.20 × 107 z – 3.60 × 1015 t) T.What is the average intensity of the beam?

The magnetic field of a beam emerging from a filter facing a floodlight is given by
B₀ = 12 × 10^–8 sin (1.20 × 10⁷ z – 3.60 × 10¹⁵ t) T.

What is the average intensity of the beam?