You are given a 2μF parallel plate capacitor. How would you establish an instantaneous displacement current of 1mA in the space between its plates?
Given:
Capacitance, C=2μF
Displacement current, Id=1 mA
Calculation:
The value of charge is given by,
Q= C V
Id dt = C dV
Thus, by applying variable potential difference of 500 V/s, the displacement current of required value can be produced.
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