and are two equilateral triangles such that D is the mid-point of BC. The ratio of the areas of triangles ABC and BDE is

Given ΔABC and ΔBDE are two equilateral triangles such that D is the midpoint of BC.



Since the given triangles are equilateral, they are similar triangles.


And also since D is the mid-point of BC, BD = DC.


We know that the ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.







ar (ΔABC): ar (ΔBDE) = 4: 1

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