, ar () = 9 cm2, ar () = 16 cm2. If BC = 2.1 cm, then the measure of EF is

Given Ar (ΔABC) = 9 cm2, ar (ΔDEF) = 16 cm2 and BC = 2.1 cm


We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.





∴ EF = 2.8 cm

1