Given that one side of isosceles right triangle is 4√2 cm.

We know that in isosceles triangle two sides are equal.

In isosceles triangle ABC, let AB and AC be two equal sides of measure 4√2 cm.

We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Now, in right triangle ABC,

⇒ BC² = AB² + AC²

⇒ BC² = (4√2)² + (4√2)²

= 32 + 32

= 64

∴ BC = 8 cm