A man goes 24 m due west and then 7 m due north. How far is he from the starting point?

Given a man goes 24 m due west and then 7 m due north.



We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.


Now, in right triangle ABC,


BC2 = AB2 + AC2


= 242 + 72


= 576 + 49


= 625


BC = 25 m

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