A man goes 24 m due west and then 7 m due north. How far is he from the starting point?
Given a man goes 24 m due west and then 7 m due north.
We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Now, in right triangle ABC,
⇒ BC2 = AB2 + AC2
= 242 + 72
= 576 + 49
= 625
∴ BC = 25 m