In an isosceles triangle ABC if AC = BC and AB2 = 2AC2 , then =
Given in isosceles ΔABC, AC = BC and AB2 = 2AC2
In isosceles ΔABC,
AC = BC, so ∠B = ∠A [Equal sides have equal angles opposite to them]
⇒ AB2 = 2AC2
⇒ AB2 = AC2 + AC2
⇒ AB2 = AC2 + BC2
∴ ΔABC is right angle triangle with ∠C = 90°