A chord of a circle of radius 10 cm subtends a right angle at the centre. The length of the chord (in cm) is
Given A chord of a circle of radius 10 cm subtends a right angle at the centre.
We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Now, in right triangle OAB,
⇒ AB2 = OA2 + OB2
= 102 + 102
= 100 + 100
= 200
∴ AB = 10√2 cm