A spy report about a suspected car reads as follows. “The car moved 2.00 km towards east, made a perpendicular left turn, ran for 500 m, made a perpendicular right turn, ran for 400 km and stopped”. Find the displacement of the car.
Taking unit vectors in X and Y directions as i and j, the given displacements can be written as, 
= 2i, 
=0.5j and 
=4i
Hence the resultant displacement vector OC = 
=2i +0.5j+4i =6i+0.5j
Magnitude of the displacement = 
=
= 6.02 km
Angle between resultant displacement and east (x-axis) is given by tanθ = (0.5/6) =1/12,
Therefore, θ=tan-1(1/12)
2