Two vectors have magnitudes 2 m and 3 m. The angle between them is 60o. Find (a) the scalar product of the two vectors, (b) the magnitude of theft vector product.

Let the magnitudes of two vectors be, =2 m and =3 m

θ= angle between the vectors =60°.


(a) The scalar product of the two vectors is given by ab cosθ = 2.3. Cos60° = 3 m �.


(b) The magnitude of their vector product is = ab Sinθ =2.3 Sin60° = = m �.


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