A heavy ring of mass m is damped on the periphery of a light circular disc. A small particle having equal mass is clamped at the centre of the disc. The system is rotated in such a way that the centre moves in a circle of radius r with a uniform speed υ. We conclude that an external force
We know that the system centre of mass will lie between the peripheri and
the centre. And it will revolve in a circle of radius r. Now, for the rotation,
there must be a centrifugal force. And,
Fext= Fcentrifugal =
Here, total mass of the system = 2m
So, Fext =