A heavy ring of mass m is damped on the periphery of a light circular disc. A small particle having equal mass is clamped at the centre of the disc. The system is rotated in such a way that the centre moves in a circle of radius r with a uniform speed υ. We conclude that an external force


We know that the system centre of mass will lie between the peripheri and


the centre. And it will revolve in a circle of radius r. Now, for the rotation,


there must be a centrifugal force. And,


Fext= Fcentrifugal =


Here, total mass of the system = 2m


So, Fext =

1