A block at rest explodes into three equal parts. Two parts start moving along X and Y axes respectively with equal speeds of 10 m/s. Find the initial velocity of the third part.

Initial momentum Pi = 0 kg m/s

Let the mass of each part be m kg and velocity of the third part be vxî + vyĵ


Final momentum Pf = 10m î + 10m ĵ + m(vx î +vy ĵ)


Applying conservation of momentum, pi = pf


0 = 10m î + 10m ĵ + m(vx î +vy ĵ)


vx î +vy ĵ = -10 î -10 ĵ


vx = -10 and vy = -10


Magnitude of velocity of third part


Angle with the horizontal =


= 135° from positive x axis or 45° below the x axis.


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