A block at rest explodes into three equal parts. Two parts start moving along X and Y axes respectively with equal speeds of 10 m/s. Find the initial velocity of the third part.
Initial momentum Pi = 0 kg m/s
Let the mass of each part be m kg and velocity of the third part be vxî + vyĵ
Final momentum Pf = 10m î + 10m ĵ + m(vx î +vy ĵ)
Applying conservation of momentum, pi = pf
0 = 10m î + 10m ĵ + m(vx î +vy ĵ)
vx î +vy ĵ = -10 î -10 ĵ
⇒ vx = -10 and vy = -10
Magnitude of velocity of third part
Angle with the horizontal =
= 135° from positive x axis or 45° below the x axis.