Two blocks of masses m1 and m2 are connected by a spring of spring constant k (figure 9-E15). The block of mass m2 is given a sharp impulse so that it acquires a velocity u0 towards right. Find (a) the velocity of the center of mass, (b) the maximum elongation that the spring will suffer.


Given that there are two blocks of mass m1 and m2 respectively,


Block of mass m2 is moving with velocity v0 while m1 is at rest initially.


K is the spring constant.


{a} Velocity of center of mass will be:




{b} The spring will attain maximum elongation when both the blocks will attain the velocity of centre of mass,


Let x be the maximum elongation of spring


Then, by energy conservation law


Change in kinetic energy = potential energy stored in spring






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