A particles on a stretched string supporting a travelling wave takes 50 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 20 cm. Find the frequency, the wavelength and the wave speed.

50 Hz, 40 cm, 20 m s1

It reaches from mean position to the crest at 5ms. So, the time period will be,


Time taken from (mean -> crest -> mean -> trough->mean)


Hence T=20ms.


So, the frequency of vibration will be,



Any two neighbouring mean positions always remain at half of the wave length.


So,



The wave speed will be,




1