A 40 cm wire having a mass of 32 g is stretched between two fixed supports 4005 cm apart. In its fundamental mode, the wire vibrates at 220 Hz. If the area of cross section of the wire is 10 mm2, find its Young modulus.

Mass per unit length,


Change in the length,


We know that,


Strain=


Now,


We know here, f, L, m.


Equating these, we get,


T=248.19 N


Now,


So, Young’s modulus =


1