A capacitor of 4 μ F is connected in a circuit as shown. The internal resistance of the battery is 0.5 Ω. The amount of charge on the capacitor plates will be

Question

Philoid · Accepted Answer

In steady state, there will be no current in the capacitor branch

Net resistance of the circuit

Current drawn from the cell

A capacitor of 4 μ F is connected in a circuit as shown. The internal resistance of the battery is 0.5 Ω. The amount of charge on the capacitor plates will be

Potential drop across two parallel branches

So, charge on the capacitor plates

Under steady state capacitor becomes open circuited therefore whatever V_c (capacitor voltage) you need it is nearly equal to V₁

∴ correct answer is 8μC

A capacitor of 4 μ F is connected in a circuit as shown. The internal resistance of the battery is 0.5 Ω. The amount of charge on the capacitor plates will be

Potential drop across two parallel branches

So, charge on the capacitor plates

Under steady state capacitor becomes open circuited therefore whatever Vc (capacitor voltage) you need it is nearly equal to V1

∴ correct answer is 8μC

Under steady state capacitor becomes open circuited therefore whatever V_c (capacitor voltage) you need it is nearly equal to V₁