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The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms-1 and 10 m s-2 at a certain instant. Find the amplitude and the time period of the motion.
4.9 cm, 0.28 s
Given,
x = 2 cm,
v = 1 m/s = 100 cm/s., and
a = 10 m/s2. = 1000 cm/s2.
Using the Formula,
negative symbol was just to show that the force is opposing in nature.
∴
Now,
∴