The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms -1 and 10 m s -2 at a certain instant. Find the amplitude and the time period of the motion.

Question

Philoid · Accepted Answer

4.9 cm, 0.28 s

Given,

x = 2 cm,

v = 1 m/s = 100 cm/s., and

a = 10 m/s². = 1000 cm/s².

Using the Formula,

negative symbol was just to show that the force is opposing in nature.

∴

Now,

∴

The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms-1 and 10 m s-2 at a certain instant. Find the amplitude and the time period of the motion.

The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms^-1 and 10 m s^-2 at a certain instant. Find the amplitude and the time period of the motion.