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A block of mass 0.5 kg hanging from a vertical spring executes simple harmonic motion of amplitude 0.1 m and time period 0.314 s. Find the maximum force exerted by the spring on the block.
25 N
Given that,
A=0.1m
m=0.5kg.
T=0.314s
For maximum restoring force the elongation must be equal to A.
Because we have to find the maximum force exerted by the spring.
We know,
Now,
From equation. (1)
F=kA
Now,
The maximum force exerted by spring on block.