A block of mass 0.5 kg hanging from a vertical spring executes simple harmonic motion of amplitude 0.1 m and time period 0.314 s. Find the maximum force exerted by the spring on the block.

25 N

Given that,


A=0.1m


m=0.5kg.


T=0.314s


For maximum restoring force the elongation must be equal to A.




Because we have to find the maximum force exerted by the spring.


We know,






Now,


From equation. (1)


F=kA




Now,


The maximum force exerted by spring on block.




1