The pendulum of a certain clock has time period 2.04 s. How fast OF Blow does the clock run during 24 hours?
28.3 minutes slow
Time period of given clock T1 =2.04 sec
We know time period of normal clock T =2.00 sec
∴ Time lag ∆T = T1-T = 2.04-2.00
= 0.04sec per oscillation
Number of oscillations in a day = 24×60×60×0
N = 43200
∴ total time lag = ∆T×N
= (0.04) × (43200)
= 1728 sec
= 28.8 minutes
∴ The given clock is 28.8 minutes slower than normal standard clock.