A pendulum clock giving correct time at a place where g = 9.800 m s-2 is taken to another place where it loses 24 seconds during 24 hours, Find the value of g at this new place.
9.795 m s-2
When the clock is at g = 9.8 m/s2 T = 2.00 sec
When clock is at g1 it loses 24 seconds in 24 hours
We have T = 2∏ T1 =
l = . g --------->1 = 2.000
This length does not change in the new place T12
l = (T12/4∏2). g1--------->2
From 1 and 2
. g = . g1
g1 = (T2 /T12) . g
=
=
= 9.746 m/s2