Three simple harmonic motions of equal amplitudes A and equal time periods in the same direction combine. The phase of the second motion is 60o ahead of the first and the phase of the third motion is 60° ahead of the second. Find the amplitude of the resultant motion.
2 A
let the S.H.Ms be
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Resultant will be x = ![]()
Resultant amplitude between first two will be
R = ![]()
R = ![]()
= ![]()
=
A
Resultant amplitude of all three S.H.Ms will be the resultant of R and ![]()
Let
be the resultant of all three S.H.Ms then,
[ angle between
will be 60° + 30° ]
= ![]()
= 2A