A uniform rod is kept vertically on a horizontal smooth surface at a point O. If it is rotated slightly and released, it falls down on the horizontal surface. The lower end will remain

The rod is uniform and the length is l. So, the center of mass is at l/2 distance. The equation of motion,



As, the force on center of mass is in –j direction, it falls directly on the point O. Hence, the end is at a distance l/2.

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