When a force of 6.0 N is exerted at 30o to a wrench at a distance of 8 cm from the nut, it is just able to loosen the nut. What force F would be sufficient to loosen it if it acts perpendicularly to the wrench at 16 cm from the nut?


The force acting on the end of the wrench is 1.5 N


Given


The force exerted into the wrench is given as, the angle of motion is. The distance from the nut to the wrench end is.


Formula Used


The formula used is that of a torque which tells us the mechanics of force which helps the object to rotate. The formula is



where


F is the force applied on the object; r is the radius of the object turning. Turning angle is given by


Explanation


The torque acting on the point A is given as






Now the torque acting on the point B is






Therefore, the force acting on the end of the wrench is 1.5 N


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