The resultant torque equivalent to 0.54 Nm

Given

The force acting on the heart shaped body as shown in the diagram 10-E2 is given as 10N, 15N, 5N, 20N. The lengths on which the forces applied are 4cm, 4cm, 3cm and 6 cm respectively.

Formula Used

The formula used is that of a torque which tells us the mechanics of force which helps the object to rotate. The formula is

where

F is the force applied on the object; r is the radius of the object turning. Turning angle is given by

Explanation

The torque acting on the point O due to the force of 15N is

The torque acting on the point O due to the force of 10N is

The torque acting on the point O due to the force of 20N is

Due to torque negation between and which leaves them to zero, leaving the resultant torque equivalent to 0.54 Nm.