A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. Find the angular deceleration and the angular velocity 5 seconds after the application of the torque.

The angular deceleration is -1 rev/sec2 and angular velocity is 5 rev/sec


Given


The wheel rotates at a speed of 600 rpm, at constant torque for 10 seconds.


Formula Used


The formula used is same as that of the formula for the relationship of velocity and acceleration in basic kinematics.



where


The initial velocity of the motion is denoted by ω and the final velocity is denoted by ω0


Explanation


First let us find the angular acceleration of the rotating wheel which is



The angular velocity is taken in terms of rad/sec which is 10 and the time taken to rotate is 10 sec




Now finding the angular deceleration after 5 seconds we get




1