A wheel of mass 10 kg and radius 20 cm is rotating at an angular speed of 100 rev/mm when the motor is turned oft Neglecting the friction at the axle, calculate the force that must be applied tangentially to the wheel to bring it to rest in 10 revolutions.
The force applied is 0.87N
Given
The mass of the wheel is given as 10kg and the rotating speed is at 100 rev/mm, the force applied on the wheel is after 10 revolutions.
Formula Used
The formula used is that of a torque which tells us the mechanics of force which helps the object to rotate. The formula applied diagonally is
and
where
F is the force applied on the object; r is the radius of the object turning. Turning angle is given by 
, I is the moment of Inertia, L is the length at which the force is applied.
Explanation
The unit of rotation of wheel has been changed to rev/sec from rev/min converting 100 rev/min into 1.66 rev/sec.
Now taking the formula to find the acceleration we get the acceleration as
where
The value of initial velocity is taken as 3.22 rev/sec and angular distance as 10 rev. The value of the angular acceleration is given as
The moment of inertia is taken as
Now finding the force applied to the wheel is
T = Fa
