A cylinder rotating at an angular speed of 50 rev/s is brought in contact with an identical stationary cylinder. Because of the kinetic friction, torques act on the two cylinders, accelerating the stationary one and decelerating the moving one. If the common magnitude of the acceleration and deceleration be one revolution per second square, how long will it take before the two cylinders have equal angular speed?
The time taken to attain equal angular speed is 25 sec
Given
The wheel rotates at a speed angular speed of 50 rev/s, at constant torque both acting in positive and negative acceleration.
Formula Used
The formula used is same as that of the formula for the relationship of velocity and acceleration in basic kinematics.
where
The initial velocity of the motion is denoted by ω and the final velocity is denoted by ω0
Explanation
First let us find the angular velocity of the first cylinder
The time taken for the two cylinders to have equal velocity is
