A light rod of length 1 m is pivoted at its centre and two masses of 5 kg and 2 kg are hung from the ends as shown in figure (10-E3). Find the initial angular acceleration of the rod assuming that it was horizontal in the beginning.
The angular acceleration of the rod of masses are given as 
Given
The length of the rod is given as 1m and is pivoted at the center with two masses at the center of the rod as 2kg and 5kg
Formula Used
To find the formula of the frictional torque we find the product of the moment of inertia and the angular acceleration of the object as
where
is the average frictional torque, I is the moment of inertia and α is the angular acceleration.
Explanation
As the diagram shows the tension developed on the rod by the two masses we can gather that
The torque produced on both the ends can be written as
