A uniform ladder of length 10.0 m and mass 16.0 kg is resting against a vertical wall making an angle of 37o with it. The vertical wail is frictionless but the ground is rough. An electrician weighing 60.0 kg climbs up the ladder. If he stays on the ladder at a point 8.00 m from the lower end, what will be the normal force and the force of friction on the ladder by the ground? What should be the minimum coefficient of friction for the electrician to work safely?
The normal force of the ladder is 745N
The force of friction at the bottom of the ladder is 412N
The coefficient of friction is 0.533
Given
The length of the ladder is 10 m, the mass of the ladder is given as 16 kg which makes angle of 37o, the weight of the electrician is 60 kg, which stays at height of 8 cm.
Formula Used
The formula used to find the acceleration of the mass pulled/pushed is determined by the second law of Newton when the Force/Tension applied is equivalent to the product of mass and acceleration
where
F is the force of the mass in terms of reactionary force, 
is the coefficient of friction and N is the reactionary force of the object.
Explanation
The reactionary at the top of the ladder is given as 
and the reactionary force at the bottom is given as 
. Hence, the reactionary force 
Placing the value of 
in 
, we get the value as
Therefore, the force of friction 
And calculating the friction coefficient, we can calculate the value as
Hence, the friction coefficient is given as 