A uniform square plate of mass 2.0 kg and edge 10 cm rotates about one of its diagonals under the action of a constant torque of 0.10 N-m. Calculate the angular momentum and the kinetic energy of the plate at the end of the fifth second after the start.
i) The value of angular momentum is 0.5 ![]()
ii) The value of kinetic energy is 75 J
Given
Mass of the plate is given as 2kg and length of the sides of the square is 10cm with a torque of 0.10Nm.
Formula used
The of the average velocity is the basic kinematic equation of velocity, where
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and
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where
is the angular speed, I is the moment of inertia and K.E. is the kinetic energy
is the average acceleration.
Explanation
(a) To find the average momentum which is
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We need to find the values of ![]()
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Then the value of kinetic energy is given as
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