A diver having a moment of inertia of 60 kg-m 2 about an axis through its center of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg-m 2 , what will be the new angular speed?

Question

Philoid · Accepted Answer

Given:

Angular speed (ω₁) =2 rad/s

Moment of inertia (I₁) = 60 kg-m²

Moment of inertia (I₂) = 5.0 kg-m²

New angular speed (ω₂) =?

Since external torque is zero

A diver having a moment of inertia of 60 kg-m2 about an axis through its center of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg-m2, what will be the new angular speed?

A diver having a moment of inertia of 60 kg-m² about an axis through its center of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg-m², what will be the new angular speed?