A uniform rod pivoted at its upper end hangs vertically. It is displaced through an angle of 600 and then released. Find the magnitude of the force acting on a particle of mass dm at the tip of the rod when the rod makes an angle of 370 with the vertical.


Given:


Length of the rod= L


Mass of the rod= m


Initial angle of displacement = 600


By the law of conservation of energy









Torque acting on the rod is given as




We know, T=Iα, angular acceleration is




centrifugal force F1 = dm (= 0.9 dmg


tangential force F2 = dm ( = 0.9 dmg


Total Force on dm= dm



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