A uniform rod pivoted at its upper end hangs vertically. It is displaced through an angle of 600 and then released. Find the magnitude of the force acting on a particle of mass dm at the tip of the rod when the rod makes an angle of 370 with the vertical.
Given:
Length of the rod= L
Mass of the rod= m
Initial angle of displacement = 600
By the law of conservation of energy
Torque acting on the rod is given as
We know, T=Iα, angular acceleration is
centrifugal force F1 = dm (= 0.9 dmg
tangential force F2 = dm ( = 0.9 dmg
Total Force on dm= dm