## Book: HC Verma - Concepts of Physics Part 1

### Chapter: 18. Geometrical Optics

#### Subject: Physics - Class 11th

##### Q. No. 22 of Exercises

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22
##### Consider the situation in figure (18-E7). The bottom of the pot is a reflecting plane mirror, S is a small fish and T is a human eye. Refractive index of water is μ.(a) At what distance(s) from itself will the fish see the image(s) of the eye?(b) At what distance(s) from itself will the eye see the image(s) of the fish?

Given, Refractive Index of water = μ

Height of the pot = H

(a)Let, x = distance of the image of the eye formed above the surface as seen by the fish

So,

Or,

Distance of the direct image =+

Similarly, distance of image through mirror =

=

(b)Let, y = distance of the image of fish below the surface as seen by eye.

So, y =

Direct image formed

Now, again another image of fish will be formed below the mirror. So, the real depth for that image of fish becomes

So, the apparent depth for the surface of water

Distance of image from the eye

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