Find the acceleration of a particle placed on the surface of the earth at the equator due to earth’s rotation. The diameter of earth = 12800 km and it takes 24 hours for the earth to complete one revolution about its axis.
Radius of earth, R = Diameter of earth/2
= 12800/2 km
= 6400 km
= 6.4 × 106 m
Time taken for one rotation (revolution about its axis), T = 24 hours = 24 × 60 ×60 secs
T = 86400 secs
Angular velocity of the particle, ω = 2π/T
Acceleration of the particle = Rω2
= 0.0338 m/s2
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