A block of weight 100 N is slowly slid up on a smooth incline of inclination 37o by a person. Calculate the work done by the person in moving the block through a distance of 2.0 m, if the driving force is (a) parallel to the incline and (b) in the horizontal direction.

asa1.png


(a.) Work done = Force along the line of displacement × displacement


=100sin37° × 2=120.363005 ≈120 J


(b.) Work done will be the same as above. This is so because the component of force along the line of displacement will still be the same i.e.100sin37°.


1