A block of mass 5.0 kg is suspended from the end of a vertical spring which is stretched by 10 cm under the load of the block. The block is given a sharp impulse from below so that it acquires an upward speed of 2.0 m/s. How high will it rise? Take g = 10 m/s2.
Let the height to which the block will rise be h.
Mass of the block, m = 5 kg
Upward speed of the block, v = 2 m/s
The potential energy of the spring gets converted into kinetic energy of the block
⇒ mgh = 1/2 mv2
⇒
⇒ h = 0.2 m
∴ The block will rise up to 0.2 m or 20cm