The heights of mercury surfaces in the two arms of the manometer shown in figure (13-E1) are 2 cm and 8 cm. Atmospheric pressure = 101 × 10 N m^-2. Find (a) the pressure of the gas in the cylinder and (b) the pressure of mercury at the bottom of the U tube.

Question

Philoid · Accepted Answer

(a)The pressure of gas is the sum of the atmospheric pressure (from the open end) and the pressure in the mercury column.

Therefore,

Here, density of mercury, , heights .

(ANS)

(b)The pressure at the bottom is given by the sum of the atmospheric pressure and the pressure in the open column.

(ANS)

The heights of mercury surfaces in the two arms of the manometer shown in figure (13-E1) are 2 cm and 8 cm. Atmospheric pressure = 101 × 10 N m-2. Find (a) the pressure of the gas in the cylinder and (b) the pressure of mercury at the bottom of the U tube.

The heights of mercury surfaces in the two arms of the manometer shown in figure (13-E1) are 2 cm and 8 cm. Atmospheric pressure = 101 × 10 N m^-2. Find (a) the pressure of the gas in the cylinder and (b) the pressure of mercury at the bottom of the U tube.