Refer to the previous problem. Suppose, the goldsmith argues that he has not mixed copper or any other material with gold, rather some cavities might have been left inside the ornament. Calculate the volume of the cavities left that will allow the weights given in that problem.

Question

Philoid · Accepted Answer

Here, instead of considering a volume for copper, we consider a volume for cavities(v). All of weight is due to gold. There volume of gold,

The total volume, —————(1)

Weight of the water displaced, —————(2)

The ornament weighs 34 g in water.

Therefore, the buoyant force, —————(3)

This buoyant force is equal to weight of the water displaced. Therefore, Equating (2) and (3)

(ANS)