A cube of ice floats partly in water and partly in K.oil (figure 13-E5). Find the ratio of the volume of ice immersed in water to that in K.oil. Specific gravity of K.oil is 0.8 and that of ice is 0.9.
Here, let the volume of cube immersed in water be 
and the volume immersed in K. Oil be 
The weight of the ice would be balanced by the buoyant forces from the oil and the water.
Density of ice, 
The weight of the cube of ice is given by, 
—————(1)
Density of water, 
Density of K.oil, 
The total buoyant force(
) is the sum of the forces exerted by the liquids.
—————(2)
This buoyant force is equal to the weight of the cube of ice.
Equating (1) and (2)
Therefore, the ratio of the volumes immersed is 1:1.
1