A cubical box is to be constructed with iron sheets 1 mm in thickness. What can be the minimum value of the external edge so that the cube does not sink in Water? Density of iron = 8000 kg m -3 and density of water = 1000 kg m -3 .

Question

Philoid · Accepted Answer

Let the edge of the iron sheet be “x cm”. To find the weight of the box, we need to find the total surface area of the cube as we are using sheets here.

Surface area =

Volume of the iron sheets,

Density of iron,

Therefore, mass of the iron box is, —————(1)

The volume of the cube is

Density of water ,

therefore, the buoyant force is, ——————(2)

The buoyant force is equal to the weight of the box.

Therefore, equating (1) and (2)

(ANS)

Therefore, the edge of the cube should be 4.8 cm.

A cubical box is to be constructed with iron sheets 1 mm in thickness. What can be the minimum value of the external edge so that the cube does not sink in Water? Density of iron = 8000 kg m-3 and density of water = 1000 kg m-3.

A cubical box is to be constructed with iron sheets 1 mm in thickness. What can be the minimum value of the external edge so that the cube does not sink in Water? Density of iron = 8000 kg m^-3 and density of water = 1000 kg m^-3.