Given data

Power of the glasses to have normal vision from 25 cm onwards, p = +1.5 D.

Least distance of clear vision, D = 25 cm

The focal lens of the glasses, f

She should have greater least distance of distinct vision without the glasses.

u = – 25 cm = -0.25 m

Using lens formula –

Substituting the values-

When she is not wearing glasses, the near point is 40 cm

The focal length of magnifying glass at that point becomes

(a) The maximum magnifying power, m when she uses microscope together with her glass –

Since, she is using magnifying glass with clear distance of vision 25cm, so

D = 25 cm

f = 5 cm

Substituting the values-

Hence, the magnifying power when object is viewed using both glasses and microscope is 6D

(b) Without the glasses, the clear distance of vision , D = 40 cm as she uses only microscope of magnifying power m to view object

Hence, the, magnifying power when viewing object using microscope is 9D

The magnifying power is more using microscope ie,9D, hence that an object can be more clearly

seen through a microscope without using the correcting glasses