A steel rod of cross-sectional area 4 cm 2 and length 2 m in shrinks by 0.1 cm as the temperature decreases in night. If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 10 11 N m -2 .

Question

Philoid · Accepted Answer

3.8 × 10⁴ N

Given, Cross-sectional area of rod,

Length of rod,

Extension is rod,

Young modulus of steel,

Let the tension be denoted by T.

Now, we know, stress,

And strain is given by ,

Young’s modulus then becomes,

A steel rod of cross-sectional area 4 cm2 and length 2 m in shrinks by 0.1 cm as the temperature decreases in night. If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

A steel rod of cross-sectional area 4 cm² and length 2 m in shrinks by 0.1 cm as the temperature decreases in night. If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 10¹¹ N m^-2.