Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Question

Philoid · Accepted Answer

Let the original intensity of light be and that after reflection be .

Given,

We know that intensities are directly proportional to the square of the amplitude. Let the initial amplitude be and that after reflection be .

Here, k is some constant.

Therefore, and .

Now, the maximum amplitude is

And minimum amplitude is

Therefore, ratio of maximum intensity to minimum is