A particle executes a simple harmonic motion of amplitude 1.0 cm along the principal axis of a convex lens of focal length 12 cm. The mean position of oscillation is at 20 cm from the lens. Find the amplitude of oscillation of the image of the particle.

When the object is at 19 cm from the

lens let the image will be at v1

Again, when the object is at 21 cm from the lens. Let the image will be at v1

amplitude of vibration of the image is A = (32.57 – 28)/2 = 2.285 cm